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secondary 3 | A Maths
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Pls help me with this question. Thank you
Date Posted: 4 years ago
Views: 255
Pls help to look through my answer to see what is wrong with my working. Thank you
Where is the working?
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sin²x + tan²xsin²x
= sin²x(1 + tan²x)
= sin²xsec²x
= sin²x(1/cos²x)
= sin²x/cos²x
= (sinx/cosx)²
= tan²x
= sin²x(1 + tan²x)
= sin²xsec²x
= sin²x(1/cos²x)
= sin²x/cos²x
= (sinx/cosx)²
= tan²x
done
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clear
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Here is my working
Date Posted:
4 years ago
Factorise out the common term sin^2 x from the numerator
Continued from your working :
= sin²x(cos²x + sin²x)/cos²x
(factor out sin²x)
= sin²x(1)/cos²x (recall sin²x + cos²x = 1)
= tan²x
Alternatively you use the working that I've posted
= sin²x(cos²x + sin²x)/cos²x
(factor out sin²x)
= sin²x(1)/cos²x (recall sin²x + cos²x = 1)
= tan²x
Alternatively you use the working that I've posted
Thank you
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