J's answer to Nicole She's Secondary 3 A Maths Singapore question.
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sin²x + tan²xsin²x
= sin²x(1 + tan²x)
= sin²xsec²x
= sin²x(1/cos²x)
= sin²x/cos²x
= (sinx/cosx)²
= tan²x
= sin²x(1 + tan²x)
= sin²xsec²x
= sin²x(1/cos²x)
= sin²x/cos²x
= (sinx/cosx)²
= tan²x
Date Posted:
4 years ago
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