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junior college 1 | H2 Maths
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Hi, I can't do (ii) onwards. Could you kindly review this challenging question and advise working solution please? Thank you so much.
Date Posted: 2 years ago
Views: 620
Good evening Candice! I see that Boy Mow Chau has stepped in for both parts and his workings appear correct, so I won't intervene further for this question.
Yes. Thank you so much for your help Mr Eric. Really appreciate your time & effort to work on my question :)
Please take care.
Please take care.
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Good evening Candice! Here are my workings for part ii.
As it’s close to 4 am and I have six classes later today (first class starts 11:30 am, last class starts 10 pm), I will take a break from my current activity.
I will take a look at parts iii and iv when I have time (or Boy Mow Chau might drop by and give his opinion), but I strongly suspect that we would need to use the results in part ii and “simul” the two equations to get the values of lambda and mu in part iii.
As it’s close to 4 am and I have six classes later today (first class starts 11:30 am, last class starts 10 pm), I will take a break from my current activity.
I will take a look at parts iii and iv when I have time (or Boy Mow Chau might drop by and give his opinion), but I strongly suspect that we would need to use the results in part ii and “simul” the two equations to get the values of lambda and mu in part iii.
Date Posted:
2 years ago
omg. I am so sorry to trouble you Mr Eric.
Thank you so much for helping me.
I will also use your advised solution of part ii to try again myself to see if I can resolve iii and iv :)
Your working solution is very clear, I can understand almost instantly (I'm now on my way to school :))
Once again, thank u very much and pls take care.
Thank you so much for helping me.
I will also use your advised solution of part ii to try again myself to see if I can resolve iii and iv :)
Your working solution is very clear, I can understand almost instantly (I'm now on my way to school :))
Once again, thank u very much and pls take care.
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solution steps for parts (iii) & (iv).
note that vector equations for a line can have many equivalent solutions, because your reference point can be any point on the line, and your direction vector can be any multiple of the basic direction vector. therefore another person may come up with a vector equation that looks different, but could be equivalent.
the same for vector equation of plane. you can choose your reference point to be any point on the plane, and you can choose any 2 non-parallel direction vectors that are parallel to the plane.
so part (iv) can have many equivalent answers.
note that vector equations for a line can have many equivalent solutions, because your reference point can be any point on the line, and your direction vector can be any multiple of the basic direction vector. therefore another person may come up with a vector equation that looks different, but could be equivalent.
the same for vector equation of plane. you can choose your reference point to be any point on the plane, and you can choose any 2 non-parallel direction vectors that are parallel to the plane.
so part (iv) can have many equivalent answers.
Date Posted:
2 years ago
Thank you so much, Mr Chau. Let me try to digest the advised solutions :)
Thanks again and take care.
Thanks again and take care.
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