J's answer to Meredy's Secondary 4 E Maths Singapore question.
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You don't really have to. It would also be okay to leave the answer like this :
a³ = 3V/4π + b³
a³ = ³√(3V/4π + b³)
What the answer scheme is doing : making the denominator the same so when we do the cube root, it is in a single term.
a³ = 3V/4π + b³(4π/4π)
a³ = 3V/4π + 4πb³/4π
a³ = (3V + 4πb³)/4π
a = √((3V + 4πb³)/4π)
a³ = 3V/4π + b³
a³ = ³√(3V/4π + b³)
What the answer scheme is doing : making the denominator the same so when we do the cube root, it is in a single term.
a³ = 3V/4π + b³(4π/4π)
a³ = 3V/4π + 4πb³/4π
a³ = (3V + 4πb³)/4π
a = √((3V + 4πb³)/4π)
Date Posted:
3 years ago
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