J's answer to cherry's Secondary 3 A Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
3eˣ + eʸ = 10 ①
2eˣ - eʸ = 5 ②
① + ② :
3eˣ + eʸ + 2eˣ - eʸ = 10 + 5
5eˣ = 15
eˣ = 3
Sub eˣ = 3 into ①,
3(3) + eʸ = 10
9 + eʸ = 10
eʸ = 1
Therefore, 4e⁵ˣ⁺³ʸ
= 4 e⁵ˣ e³ʸ
= 4 (eˣ)⁵ (eʸ)³
= 4 (3⁵) (1³)
= 4 (243) (1)
= 972
2eˣ - eʸ = 5 ②
① + ② :
3eˣ + eʸ + 2eˣ - eʸ = 10 + 5
5eˣ = 15
eˣ = 3
Sub eˣ = 3 into ①,
3(3) + eʸ = 10
9 + eʸ = 10
eʸ = 1
Therefore, 4e⁵ˣ⁺³ʸ
= 4 e⁵ˣ e³ʸ
= 4 (eˣ)⁵ (eʸ)³
= 4 (3⁵) (1³)
= 4 (243) (1)
= 972
Date Posted:
3 years ago
thank you !!
360 Tutoring Program