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secondary 3 | A Maths
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i need help with question 10
Date Posted: 3 years ago
Views: 183
Hold on. Will type out the answer soon
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3eˣ + eʸ = 10 ①
2eˣ - eʸ = 5 ②
① + ② :
3eˣ + eʸ + 2eˣ - eʸ = 10 + 5
5eˣ = 15
eˣ = 3
Sub eˣ = 3 into ①,
3(3) + eʸ = 10
9 + eʸ = 10
eʸ = 1
Therefore, 4e⁵ˣ⁺³ʸ
= 4 e⁵ˣ e³ʸ
= 4 (eˣ)⁵ (eʸ)³
= 4 (3⁵) (1³)
= 4 (243) (1)
= 972
2eˣ - eʸ = 5 ②
① + ② :
3eˣ + eʸ + 2eˣ - eʸ = 10 + 5
5eˣ = 15
eˣ = 3
Sub eˣ = 3 into ①,
3(3) + eʸ = 10
9 + eʸ = 10
eʸ = 1
Therefore, 4e⁵ˣ⁺³ʸ
= 4 e⁵ˣ e³ʸ
= 4 (eˣ)⁵ (eʸ)³
= 4 (3⁵) (1³)
= 4 (243) (1)
= 972
thank you !!
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