Bryant Lam Hong Sheng's answer to sara's Secondary 3 A Maths Singapore question.
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As long as k <1, there will be no solution to the equation
Date Posted:
3 years ago
Actually for no solution,
-1 < k < 0 or 0 < k < 1
i.e 0< |k|< 1
k < 1 only will include values like k = -2
when k = -2, sin x = -1/-2 = ½ , which has a solution
-1 < k < 0 or 0 < k < 1
i.e 0< |k|< 1
k < 1 only will include values like k = -2
when k = -2, sin x = -1/-2 = ½ , which has a solution
Strictly speaking, it is not possible for k to be 0 since that results in 1/sinx = 0, which does not make sense since a non-zero numerator will never give a result of 0
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