Fionella Foo Ying Lun's answer to flryna's Secondary 2 Maths question.
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when it is PROPORTIONAL, multiply k with the x^2.
when it is inversely proportional, it will be 1/[k(x^2)] instead.
solve for k with the x and y values that are given.
when the question has x^2, there are always 2 values; one positive value and one negative value.
when it is inversely proportional, it will be 1/[k(x^2)] instead.
solve for k with the x and y values that are given.
when the question has x^2, there are always 2 values; one positive value and one negative value.
Date Posted:
7 years ago
thankyou so much !!
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