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secondary 2 | Maths
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rlly needa get this done asap !1!1
Date Posted: 6 years ago
Views: 377
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done
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when it is PROPORTIONAL, multiply k with the x^2.
when it is inversely proportional, it will be 1/[k(x^2)] instead.
solve for k with the x and y values that are given.
when the question has x^2, there are always 2 values; one positive value and one negative value.
when it is inversely proportional, it will be 1/[k(x^2)] instead.
solve for k with the x and y values that are given.
when the question has x^2, there are always 2 values; one positive value and one negative value.
Date Posted:
6 years ago
thankyou so much !!
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