Lee Han Min's answer to Nancy Bo's Secondary 2 Maths Singapore question.

done {{ upvoteCount }} Upvotes
clear {{ downvoteCount * -1 }} Downvotes
Lee Han Min
Lee Han Min's answer
11 answers (Tutor Details)
Hi Nancy!
For similar triangles the naming matters! So if it says ABD is similar to BCD, it means

Line AB is similar to the line BC;
Line BD is similar to line CD;
Line DA is similar to line DB.

Same for the angles!
So the solution :

Angle ABC = Angle ABD + Angle CBD

But since triangle ABD is similar to triangle BCD.
That means Angle CBD is the same as Angle BAD.

So Angle ABC = Angle ABD + Angle BAD

Angle ABD + Angle BAD = 180° - Angle BCA = 90°
(total internal angles of a triangle = 180°)

So Angle ABC = 90°