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secondary 2 | Maths
3 Answers Below
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Date Posted: 3 years ago
Views: 215
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Date Posted:
3 years ago
Hi Nancy!
For similar triangles the naming matters! So if it says ABD is similar to BCD, it means
Line AB is similar to the line BC;
Line BD is similar to line CD;
Line DA is similar to line DB.
Same for the angles!
So the solution :
Angle ABC = Angle ABD + Angle CBD
But since triangle ABD is similar to triangle BCD.
That means Angle CBD is the same as Angle BAD.
So Angle ABC = Angle ABD + Angle BAD
Angle ABD + Angle BAD = 180° - Angle BCA = 90°
(total internal angles of a triangle = 180°)
So Angle ABC = 90°
For similar triangles the naming matters! So if it says ABD is similar to BCD, it means
Line AB is similar to the line BC;
Line BD is similar to line CD;
Line DA is similar to line DB.
Same for the angles!
So the solution :
Angle ABC = Angle ABD + Angle CBD
But since triangle ABD is similar to triangle BCD.
That means Angle CBD is the same as Angle BAD.
So Angle ABC = Angle ABD + Angle BAD
Angle ABD + Angle BAD = 180° - Angle BCA = 90°
(total internal angles of a triangle = 180°)
So Angle ABC = 90°
done
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Hope this helps. Please add in comments if you have any questions
Date Posted:
3 years ago
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