Muhd Ilman Fahmi's answer to Rxndxm's Secondary 3 A Maths question.
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Equate both equations to get the solutions. Since its a tangent, it only has one solution.
With the quadratic equation you get:
0= x^2 - 2k^2x + k^4
You can either use perfect square to find the solution, or use b^2 - 4ac = 0.
If you use b^2 - 4ac =0, you get
4k^4 - 4(1)(4k^4) = 0.
Since this equation is true regardless of any value of k, k is from negative infinity to positive infinity
Hope it helps!
With the quadratic equation you get:
0= x^2 - 2k^2x + k^4
You can either use perfect square to find the solution, or use b^2 - 4ac = 0.
If you use b^2 - 4ac =0, you get
4k^4 - 4(1)(4k^4) = 0.
Since this equation is true regardless of any value of k, k is from negative infinity to positive infinity
Hope it helps!
Date Posted:
6 years ago
Thx
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