Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | A Maths
2 Answers Below
Anyone can contribute an answer, even non-tutors.
How to do Qn 2 and 4b????
Qn 4b wants to find the value of p and k
Date Posted: 7 years ago
Views: 861
See 2 Answers
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Equate both equations to get the solutions. Since its a tangent, it only has one solution.
With the quadratic equation you get:
0= x^2 - 2k^2x + k^4
You can either use perfect square to find the solution, or use b^2 - 4ac = 0.
If you use b^2 - 4ac =0, you get
4k^4 - 4(1)(4k^4) = 0.
Since this equation is true regardless of any value of k, k is from negative infinity to positive infinity
Hope it helps!
With the quadratic equation you get:
0= x^2 - 2k^2x + k^4
You can either use perfect square to find the solution, or use b^2 - 4ac = 0.
If you use b^2 - 4ac =0, you get
4k^4 - 4(1)(4k^4) = 0.
Since this equation is true regardless of any value of k, k is from negative infinity to positive infinity
Hope it helps!
Date Posted:
7 years ago
Thx
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Since the equation is less than 0 from 4 to k, the solutions of the equation are 4 and k. From there you can find the values of k and p by substituting the appropiate values. Hope it helps!
Date Posted:
7 years ago
360 Tutoring Program