Khir Zulkifli's answer to Sonia's Junior College 1 H2 Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Hi I have given a helping hand by solving 2 questions. For implicit differentiation if it’s d/dx(dy/dy) you will just get the second order of differentiation so it’s d^2y/dx^2.
Date Posted:
4 years ago
d/dx (dy/dx) rather than d/dx (dy/dy)
Yup a mistake there! Sorry my bad, Thanks!
No worries, just helping
A number of my Sec 4 students think that dy/dx (dy/dx) is no different from d/dx (dy/dx). When they started learning it they did not think that it would actually be different. It’s not that explicitly taught in Sec 4.
It is important to recognise that d/dx is an operator, not a fraction
dy/dx means the operator has been applied on y already. Hence dy/dx (dy/dx)
Is simply (dy/dx)²
Whereas d/dx (dy/dx) is an operation on the first derivative. This leads to the second derivative which is represented by d²y/dx² (also can be seen to be applying the operator twice on y itself).
Teachers should have made this clear in O level teaching.
Is simply (dy/dx)²
Whereas d/dx (dy/dx) is an operation on the first derivative. This leads to the second derivative which is represented by d²y/dx² (also can be seen to be applying the operator twice on y itself).
Teachers should have made this clear in O level teaching.
360 Tutoring Program