Yes second one is easy

To add,

There are three formats to consider.

1. y = ax² + bx + c
2. y = a (x + b) (x + c)
3. y = a (x + h)^2 + k

Which is the best approach to use, or are there times where one approach is preferred?

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1. y = ax² + bx + c

This approach is preferred when the y-intercept of the graph is provided and two other points on the curve are provided, as is the case in this question.

If (0, -6) is a point on the curve, then c = -6.

We use the other two points (-4, 10) and (2, 10) to form two simuls in two unknowns and solve.

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2. y = a (x + b) (x + c)

This approach is preferred when the TWO x-intercepts are provided and one more point is provided.

Suppose the x-intercepts are -3 and 1. Then we have y = a (x + 3) (x - 1). We use the third coordinate to obtain the value of a.

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3. y = a (x + h)^2 + k

This approach is preferred when the turning point of the curve is provided and one other point is provided.

If the turning point of the curve is (-1, -8), then by default, h = 1 and k = -8.

Now we have one unknown a left, and we just need one other coordinate (0, -6) to obtain the value of a.

Take note of these as it simplifies your workings greatly.

Thank you for going the extra mile to help me out. Thank you so mucb