Lim En Jie's answer to Koyuki Sky's Secondary 3 A Maths Singapore question.
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I initially made the mistake of equating each sqrt to 0 which is wrong. Think the approach for this question is to consider the “cases” in which this equation would be true. Each sqrt must be ≤ to 2 or = 0 (but not negative since you dealing with positive sqrt). That being said, you will be able to form inequalities to solve for b^2-4ac of which you’d realise the first sqrt has no real roots that satisfy the given equation “=2”. What a question lol there’s quite a line to connect for the dots they provide.
Date Posted:
4 years ago