Eric Nicholas K's answer to Imaboss's Secondary 4 E Maths Singapore question.
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Part iv is a bit unusual, but I am very sure that A + B will be 90 degrees in the calculation if we were to use a calculator and both angles A and B are acute.
Date Posted:
4 years ago
Can the last part be 1/tan (a+b)
= 1/(1/tanb) ->from part1
= tan b
=1/2
= 1/(1/tanb) ->from part1
= tan b
=1/2
I took it that part ii and the remaining parts are not related though, since the case in part ii leads to tan B = -1/3 whereas it is given for parts iii and iv that tan B = 1/2, so I presume they are meant for different parts
In short, the equation for part ii does not hold true for parts iii and iv, since the values for tan B are not the same for parts ii and iv.
Okay noted w thanks
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