Chester's answer to Shan Kuek's Secondary 3 A Maths Singapore question.
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Rearranging, we get
x^2 - 2x + (6-m) > 0
By using b^2 - 4ac < 0 to find no real roots,
We get
(-2)^2 - 4(1)(6-m) < 0
4 - (24-4m) < 0
4m < 20
m < 5
x^2 - 2x + (6-m) > 0
By using b^2 - 4ac < 0 to find no real roots,
We get
(-2)^2 - 4(1)(6-m) < 0
4 - (24-4m) < 0
4m < 20
m < 5
Date Posted:
4 years ago
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