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secondary 3 | A Maths
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Please help me with 2(b)
Date Posted: 4 years ago
Views: 525
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Rearranging, we get
x^2 - 2x + (6-m) > 0
By using b^2 - 4ac < 0 to find no real roots,
We get
(-2)^2 - 4(1)(6-m) < 0
4 - (24-4m) < 0
4m < 20
m < 5
x^2 - 2x + (6-m) > 0
By using b^2 - 4ac < 0 to find no real roots,
We get
(-2)^2 - 4(1)(6-m) < 0
4 - (24-4m) < 0
4m < 20
m < 5
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