AC Lim's answer to Joyce's Primary 6 Maths Data Analysis Singapore question.
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Papaya
4 for $5 (all time 3)
12 for $15
Apple
3 for $2 (all time 4)
12 for $8
For 12 papayas and 12 apples, the price different = 15-8 =$7
For total papayas and april Alfred bought, the price different =$63
Therefore total papaya or apple Alfred bought = 63÷7 = 9 sets of 12.
a) Total papayas = 9×12 =108
Total fruit = 2×108 = 216 altogether.
b) Papaya = 108×5÷4 = $135
Apple = 108×2÷3 =72
Total= 135+72 =207 altogether.
Hope this helps
4 for $5 (all time 3)
12 for $15
Apple
3 for $2 (all time 4)
12 for $8
For 12 papayas and 12 apples, the price different = 15-8 =$7
For total papayas and april Alfred bought, the price different =$63
Therefore total papaya or apple Alfred bought = 63÷7 = 9 sets of 12.
a) Total papayas = 9×12 =108
Total fruit = 2×108 = 216 altogether.
b) Papaya = 108×5÷4 = $135
Apple = 108×2÷3 =72
Total= 135+72 =207 altogether.
Hope this helps
Date Posted:
4 years ago
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