Wong YX's answer to Alice's Primary 5 Maths Singapore question.
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Since we bought an equal number of apples and oranges, we must find the number of the 2 fruits the same first. (Topic: Common Multiple)
Common multiple of 5 and 4 is 20.
Apples:
5 A → $2
20 A → $8
Oranges:
4 O → $3
20 O → $15
20 apples and 20 oranges are counted as 1 set/group.
For each set/group, the difference is:
$15 - $8 = $7
Since the total difference is $21, we could find the number of sets:
$21 ÷ $7 = 3 sets
Hence, the number of oranges bought is:
3 x 20 = 60 (a)
In total, Amelia bought 60 apples and 60 oranges. The total cost is:
$8 x 3 = $24 (60 apples)
$15 x 3 = $45 (60 oranges)
$24 + $45 = $69
Common multiple of 5 and 4 is 20.
Apples:
5 A → $2
20 A → $8
Oranges:
4 O → $3
20 O → $15
20 apples and 20 oranges are counted as 1 set/group.
For each set/group, the difference is:
$15 - $8 = $7
Since the total difference is $21, we could find the number of sets:
$21 ÷ $7 = 3 sets
Hence, the number of oranges bought is:
3 x 20 = 60 (a)
In total, Amelia bought 60 apples and 60 oranges. The total cost is:
$8 x 3 = $24 (60 apples)
$15 x 3 = $45 (60 oranges)
$24 + $45 = $69
Date Posted:
4 years ago
Thank you very much. It’s very helpful
No problem.
There was a minor typo in the 2nd sentence: “... we must *make* (not ‘find’) the number of the 2 fruits the same first.”
There was a minor typo in the 2nd sentence: “... we must *make* (not ‘find’) the number of the 2 fruits the same first.”
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