Gerald's answer to LZmath's Secondary 2 Maths Singapore question.
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in part a), the law stating that the effective resistance across 2 parallel resistors A and B) is as follows: Reffective = 1/[1/Ra+1/Rb]
after part a), we combine the resistors A and B into one effective circuit as seen to find the total resistance simply by adding to solve part b).
In part C, we use Ohm's Law (V=IR) to find the total current in the circuit which is also equal to total current in C.
In part D, we use potential dividers where the voltage across 2 points PQ = [(Rpq)/(Rtotal)]*Vtotal
The same principle can be applied in part e, or the answer can also be obtained by subtracting Vpq from the total voltage, or emf of battery.
in part f, the current in A is found by the formula ([1/Ra)/(1/Ra+1/Rb)]*(Total Current in branch)
after part a), we combine the resistors A and B into one effective circuit as seen to find the total resistance simply by adding to solve part b).
In part C, we use Ohm's Law (V=IR) to find the total current in the circuit which is also equal to total current in C.
In part D, we use potential dividers where the voltage across 2 points PQ = [(Rpq)/(Rtotal)]*Vtotal
The same principle can be applied in part e, or the answer can also be obtained by subtracting Vpq from the total voltage, or emf of battery.
in part f, the current in A is found by the formula ([1/Ra)/(1/Ra+1/Rb)]*(Total Current in branch)
Date Posted:
5 years ago
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