Chan Zhi Zhen's answer to Michael's Secondary 3 E Maths Singapore question.
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My version of the ans. you shld further consult part D with ur teacher as well :)
Date Posted:
4 years ago
For part D you only got that because of truncation errors. If you substituted the exact forms both will give back 450m².
The approach to this part should be that one value of x (≈6.37) will give you a negative value of y , while the other value of x (≈1.96) gives a positive value of y.
Since length cannot be negative, that value of x is rejected.
The approach to this part should be that one value of x (≈6.37) will give you a negative value of y , while the other value of x (≈1.96) gives a positive value of y.
Since length cannot be negative, that value of x is rejected.
Thank you for your input! Wasn't sure of part D myself
Welcome. Just helping to clarify.
sidetrack a little, if you're checking for which estimate is better (let's say given to you and not having calculated), you'll have to check the percentage error in absolute terms for each value.
sidetrack a little, if you're checking for which estimate is better (let's say given to you and not having calculated), you'll have to check the percentage error in absolute terms for each value.
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