Christmas MT's answer to Puay Xin yue's Secondary 3 E Maths Singapore question.
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I used to struggle with number patterns. But I realised if you start by calculating the difference between each term, there is a high chance you might find a pattern.
For this example, the numerator and denominator follows a different pattern. If you combine them it would be:
nth term = n / (2n - 1)
then check back to see if it fits!
For this example, the numerator and denominator follows a different pattern. If you combine them it would be:
nth term = n / (2n - 1)
then check back to see if it fits!
Date Posted:
4 years ago
Tysm!