Eric Nicholas K's answer to Kathy's Secondary 4 A Maths Singapore question.
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Q45
This question very very tricky because not only we have to find the range of values for which f’(v) is positive, we also must make sure that the square root of v3 - v2 must exist (in other words, we must solve for v3 - v2 >= 0).
Therefore, we get v >= 1 as the range of values.
This question very very tricky because not only we have to find the range of values for which f’(v) is positive, we also must make sure that the square root of v3 - v2 must exist (in other words, we must solve for v3 - v2 >= 0).
Therefore, we get v >= 1 as the range of values.
Date Posted:
4 years ago