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Q43
Date Posted:
4 years ago
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Q44
Date Posted:
4 years ago
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Q45
This question very very tricky because not only we have to find the range of values for which f’(v) is positive, we also must make sure that the square root of v3 - v2 must exist (in other words, we must solve for v3 - v2 >= 0).
Therefore, we get v >= 1 as the range of values.
This question very very tricky because not only we have to find the range of values for which f’(v) is positive, we also must make sure that the square root of v3 - v2 must exist (in other words, we must solve for v3 - v2 >= 0).
Therefore, we get v >= 1 as the range of values.
Date Posted:
4 years ago
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Q46
Date Posted:
4 years ago
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Q47
Kathy, you must not forget how to do binomial after not touching it for quite some time.
Kathy, you must not forget how to do binomial after not touching it for quite some time.
Date Posted:
4 years ago
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Q48, still halfway in (ii)
End of session. I am not free now and will continue at a much later time. You can post the next one first.
End of session. I am not free now and will continue at a much later time. You can post the next one first.
Date Posted:
4 years ago
Out now and will only continue at a much later time
This part u not yet done?
I return to do later; forgot to bring that piece of paper out
My workings are on that piece of paper and I forgot to take it out of the scanner to continue writing
Don’t forget this qns. Thanks
I do the other three first. Now going back to Q48.
I finish this, I start new chapter
Currently stuck at that question, I trying to figure out how to get sq 3 / 2 - 3, I obtained a different answer altogether
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Q48, corrected
I have worked out the last part, and I believe that the final expression is incorrect. In fact, for x < negative sqrt 3, dy/dx can go from 0 to negative infinity in value. I will upload a graph of dy/dx in a moment to show you.
I have worked out the last part, and I believe that the final expression is incorrect. In fact, for x < negative sqrt 3, dy/dx can go from 0 to negative infinity in value. I will upload a graph of dy/dx in a moment to show you.
Date Posted:
4 years ago
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Kathy, here is the proof which shows that dy/dx should be greater than, instead of less than, 0.5 sqrt 3 - 3.
Date Posted:
4 years ago
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Q48 proving part, updated for clarity
Date Posted:
4 years ago
The given question is incorrect.