YuanJie Liu's answer to Sophia's Secondary 3 A Maths question.
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when 2cosx-1=0
cosx=1/2
x = π/3 or 5π/3 (2π-π/3)
when x = (2k-1)π, it has the minimum value of 2x(-1)-1=-3
when x=2kπ, it has the maximum value of 2x1-1=1
cosx=1/2
x = π/3 or 5π/3 (2π-π/3)
when x = (2k-1)π, it has the minimum value of 2x(-1)-1=-3
when x=2kπ, it has the maximum value of 2x1-1=1
Date Posted:
7 years ago
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