Eric Nicholas K's answer to Bobby's Junior College 1 H2 Maths Singapore question.
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y is a function of x, so we must also treat 'y' as a chain.
Differentiating with respect to x,
x3 --> 3x2
x4 --> 4x3
x5 --> 5x4 and so on
y3 --> 3y2 times dy/dx
y4 --> 4y3 times dy/dx
y5 --> 5y4 times dy/dx
where 'y' is the chain and using chain rule, we have to add a 'd/dx (y) at the back which is simply dy/dx as I have put above.
Differentiating with respect to x,
x3 --> 3x2
x4 --> 4x3
x5 --> 5x4 and so on
y3 --> 3y2 times dy/dx
y4 --> 4y3 times dy/dx
y5 --> 5y4 times dy/dx
where 'y' is the chain and using chain rule, we have to add a 'd/dx (y) at the back which is simply dy/dx as I have put above.
Date Posted:
5 years ago
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