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y is a function of x, so we must also treat 'y' as a chain.

Differentiating with respect to x,

x3 --> 3x2

x4 --> 4x3

x5 --> 5x4 and so on

y3 --> 3y2 times dy/dx

y4 --> 4y3 times dy/dx

y5 --> 5y4 times dy/dx

where 'y' is the chain and using chain rule, we have to add a 'd/dx (y) at the back which is simply dy/dx as I have put above.

Differentiating with respect to x,

x3 --> 3x2

x4 --> 4x3

x5 --> 5x4 and so on

y3 --> 3y2 times dy/dx

y4 --> 4y3 times dy/dx

y5 --> 5y4 times dy/dx

where 'y' is the chain and using chain rule, we have to add a 'd/dx (y) at the back which is simply dy/dx as I have put above.

Date Posted:
11 months ago