Edwin David Goh's answer to Cindy's Primary 5 Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
This is tough! LOL
Date Posted:
6 years ago
Thank you. But I dont understand why 11 sets of ~20 = 7 sets of ~~~.
Common multiple.
11C = 3u .... x 7
7C = 1u + 20 x 11
77C = 21u
77C = 11u + 220
Hence we can say 21u = 11u + 220, 10U = 220, u = 22
11C = 3u .... x 7
7C = 1u + 20 x 11
77C = 21u
77C = 11u + 220
Hence we can say 21u = 11u + 220, 10U = 220, u = 22
Sorry, i still don't understanding, any other way to explain this question? Thank you.
360 Tutoring Program