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primary 5 | Maths
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Please help. Thank you
Date Posted: 5 years ago
Views: 281
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This is tough! LOL
Date Posted:
5 years ago
Thank you. But I dont understand why 11 sets of ~20 = 7 sets of ~~~.
Common multiple.
11C = 3u .... x 7
7C = 1u + 20 x 11
77C = 21u
77C = 11u + 220
Hence we can say 21u = 11u + 220, 10U = 220, u = 22
11C = 3u .... x 7
7C = 1u + 20 x 11
77C = 21u
77C = 11u + 220
Hence we can say 21u = 11u + 220, 10U = 220, u = 22
Sorry, i still don't understanding, any other way to explain this question? Thank you.
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