Adam Smith's answer to Soh Hao Ming's Secondary 4 E Maths question.
Oh TYS ans. Can you explain them?
For part (a), for the total to be 18, each dice has to show the number 6. Hence why the probability of the no. 6 appearing on each die is 1/6. Multiply it by itself 3 times since there are 3 dice.
What about part 3)?
Part (b), the possible outcomes are 111, 222, 333, 444, 555 and 666. The probability of each outcome happening is 1/6 × 1/6 × 1/6 = 1/216.
So u need to multiply it by 6 since there are 6 possible outcomes.
So u need to multiply it by 6 since there are 6 possible outcomes.
Part c) the possible outcomes are 665, 656 or 566. Hence why u need to multiply by 3 since there are 3 possible outcomes.
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