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secondary 4 | E Maths
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probablity thankss
Date Posted: 6 years ago
Views: 199
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Oh TYS ans. Can you explain them?
For part (a), for the total to be 18, each dice has to show the number 6. Hence why the probability of the no. 6 appearing on each die is 1/6. Multiply it by itself 3 times since there are 3 dice.
What about part 3)?
Part (b), the possible outcomes are 111, 222, 333, 444, 555 and 666. The probability of each outcome happening is 1/6 × 1/6 × 1/6 = 1/216.
So u need to multiply it by 6 since there are 6 possible outcomes.
So u need to multiply it by 6 since there are 6 possible outcomes.
Part c) the possible outcomes are 665, 656 or 566. Hence why u need to multiply by 3 since there are 3 possible outcomes.
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