Lee Wonn Jen's answer to kenzy's Secondary 3 E Maths question.
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Using the equation, s = ut + 0.5at^2, substitute in values of distance s, initial velocity u, and acceleration a.
Date Posted:
6 years ago
hi thanks for your answer :) may i ask why is the initial velocity 1/2? :) thanks
Initial velocity is 0, as the car is initially at rest.
The formula is
s = ut + 0.5at^2,
where:
s = distance = 400
u = initial velocity = 0
t = time, unknown
a = acceleration = 5
Hence,
400 = 0×t + 0.5(5)(t^2)
As you can see, 0×t = 0, so the equation is simplified to
400 = 0.5(5)(t^2)
t^2 = 160
The formula is
s = ut + 0.5at^2,
where:
s = distance = 400
u = initial velocity = 0
t = time, unknown
a = acceleration = 5
Hence,
400 = 0×t + 0.5(5)(t^2)
As you can see, 0×t = 0, so the equation is simplified to
400 = 0.5(5)(t^2)
t^2 = 160
thank you so much :))
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