Help's answer to Miri's Secondary 1 Maths Singapore question.
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For a number to be a perfect cube no. , its prime factors must have a power that is multiples of 3 .
In this case , 4312 = 2^3x7^2x11
and for it to satisfy the conditions of being a perfect cube no . , it needs multiple 7 and 2 (11) .
Thus , k = 7x11x11
= 847
In this case , 4312 = 2^3x7^2x11
and for it to satisfy the conditions of being a perfect cube no . , it needs multiple 7 and 2 (11) .
Thus , k = 7x11x11
= 847
Date Posted:
2 months ago
Hope this explanation is useful for you
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