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Secondary 1 | Maths
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Secondary 1 Maths Singapore

I need help with b) only

Date Posted: 2 months ago

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For a number to be a perfect cube no. , its prime factors must have a power that is multiples of 3 .

In this case , 4312 = 2^3x7^2x11
and for it to satisfy the conditions of being a perfect cube no . , it needs multiple 7 and 2 (11) .

Thus , k = 7x11x11
= 847

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