Yxcas's answer to lana <3's Secondary 4 A Maths Singapore question.
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Date Posted:
4 months ago
I understand but how is that chain rule?
It is the same if you are familiar with how you differentiate an equation using chain rule.
E.g.
y = (2x ² +3) ²
dy/dx = 2 (2x ² +3) x 4
You differentiate the “outside” bracket power leaving the inside as is, then multiply by the differentiation of the “inside” bracket values.
E.g.
y = (2x ² +3) ²
dy/dx = 2 (2x ² +3) x 4
You differentiate the “outside” bracket power leaving the inside as is, then multiply by the differentiation of the “inside” bracket values.
thank you!!!
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