09kaze's answer to rick's Secondary 1 Maths Singapore question.
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1. when you move the -17h to the -12h, the -17h will change sign and become positive. Same thing for the +58.
Pls let me know if you can't see/don't understand
Pls let me know if you can't see/don't understand
Date Posted:
1 month ago
i’m confused whr did the 48 come from? i thought u were supposed shift the -12 to the -17 side first? why did u take 12(h+4) ?
(Sorry. My comment got deleted earlier)
So in this case -12 can be written as -12/1. I choose to take (h-4) as the LCM for the 2 fractions, and then I multiply -12 by (h-4) = -12h + 48. The -12 have to apply to H and -4.
So in this case -12 can be written as -12/1. I choose to take (h-4) as the LCM for the 2 fractions, and then I multiply -12 by (h-4) = -12h + 48. The -12 have to apply to H and -4.
Also, the -17h and the +68 comes from multiply k= -17 to kh - 4k. Same thing with the -17 x -4 giving you positive 68. I apologise if it's a bit unclear or confusing.
ohh okok i get it now tysm. may ik wat is this method called? can u look at the wrong working ive done above and if u r able to, may u point out whr i went wrong? tysm!
My method is the sec 2 method involving addition of algebraic fractions.
Also when you move your -12 over to your -17, your -12 need to change sign because you are moving it over a equal sign. So it becomes -17 + 12 = -5, then -5 = 10/(h-4). Try to put your whole numbers on one side of the equation (left or right) and your algebra things on the other side.
Also when you move your -12 over to your -17, your -12 need to change sign because you are moving it over a equal sign. So it becomes -17 + 12 = -5, then -5 = 10/(h-4). Try to put your whole numbers on one side of the equation (left or right) and your algebra things on the other side.
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