Erfana Beevee Binte Hassan Shariff's answer to M's Primary 6 Maths Geometry Singapore question.
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Note that OB=OC=OA=radius.
Triangle OBC is an isosceles triangle with angle OBC=angle OCB=65
Angle BOC=180 - 65 - 65 = 50(sum of triangle is 180)
Angle AOB= 180 - 50 = 130(angle on str line)
See that triangle OAB is another isosceles triangle with OA=OB.
Angle BAC= (180 - 130)/2 =25.
Triangle OBC is an isosceles triangle with angle OBC=angle OCB=65
Angle BOC=180 - 65 - 65 = 50(sum of triangle is 180)
Angle AOB= 180 - 50 = 130(angle on str line)
See that triangle OAB is another isosceles triangle with OA=OB.
Angle BAC= (180 - 130)/2 =25.
Date Posted:
8 months ago
Thank you.
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