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primary 6 | Maths
| Geometry
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Angle question
Date Posted: 1 year ago
Views: 112
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Note that OB=OC=OA=radius.
Triangle OBC is an isosceles triangle with angle OBC=angle OCB=65
Angle BOC=180 - 65 - 65 = 50(sum of triangle is 180)
Angle AOB= 180 - 50 = 130(angle on str line)
See that triangle OAB is another isosceles triangle with OA=OB.
Angle BAC= (180 - 130)/2 =25.
Triangle OBC is an isosceles triangle with angle OBC=angle OCB=65
Angle BOC=180 - 65 - 65 = 50(sum of triangle is 180)
Angle AOB= 180 - 50 = 130(angle on str line)
See that triangle OAB is another isosceles triangle with OA=OB.
Angle BAC= (180 - 130)/2 =25.
Thank you.
Thank you.
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