Wei Xuan Seow's answer to lana <3's Secondary 4 A Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Using special algebraic identities, a^2 - b^2 = (a+b)(a-b)
a^2 - b^2
= (x+2)^2 - (x-3)^2
In this case, a = (x+2) and b = (x-3).
Hence,
(x+2)^2 - (x-3)^2
= [(x+2) + (x-3)] * [(x+2) - (x-3)]
= (2x-1)(5)
a^2 - b^2
= (x+2)^2 - (x-3)^2
In this case, a = (x+2) and b = (x-3).
Hence,
(x+2)^2 - (x-3)^2
= [(x+2) + (x-3)] * [(x+2) - (x-3)]
= (2x-1)(5)
Date Posted:
11 months ago
Thanks so much for the help ! i get it now
360 Tutoring Program