Gavin's answer to Brianca's Secondary 3 A Maths Singapore question.

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Gavin
Gavin's answer
2 answers (Tutor Details)
1st
The key here, is to identify at which combination of the expansion does the X's cancel out each other. Here, (X^4)^3 will nicely cancel out (1/X^2)^6 which gives you the term independent of X, which would be K^6. From there use calculator to find K.
Brianca
Brianca
9 months ago
Thanks