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Question
secondary 3 | A Maths
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Anyone can contribute an answer, even non-tutors.
Pls help.
Date Posted: 1 year ago
Views: 197
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The key here, is to identify at which combination of the expansion does the X's cancel out each other. Here, (X^4)^3 will nicely cancel out (1/X^2)^6 which gives you the term independent of X, which would be K^6. From there use calculator to find K.
Date Posted:
1 year ago
Thanks
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