J's answer to Ricky's Secondary 3 A Maths Singapore question.
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You can also do the second part like this:
a³ + 3a - 4 = 0
Sub a = 1,
1³+ 3(1) - 4 = 1 + 3 - 4 = 0
By the factor theorem, a - 1 is a factor of the polynomial.
Factorise,
(a-1)(a²+a+4) = 0
You will be able to obtain the second bracket by some trial and error once you know (a-1) is a factor.
Continue accordingly.
a³ + 3a - 4 = 0
Sub a = 1,
1³+ 3(1) - 4 = 1 + 3 - 4 = 0
By the factor theorem, a - 1 is a factor of the polynomial.
Factorise,
(a-1)(a²+a+4) = 0
You will be able to obtain the second bracket by some trial and error once you know (a-1) is a factor.
Continue accordingly.
Date Posted:
1 year ago
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