saurabh's answer to Ricky's Secondary 3 A Maths Singapore question.
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Let the other factor be x**2+px+q.
Multiply it with given eq and compare terms.
You will get p=4 and q=5.
(X**2+2x-3) (X**2+4x+5) =0
Second term is always > 0 . Check it's minimum at x= -2.
So it is going to have only 2 roots of the first term.
Multiply it with given eq and compare terms.
You will get p=4 and q=5.
(X**2+2x-3) (X**2+4x+5) =0
Second term is always > 0 . Check it's minimum at x= -2.
So it is going to have only 2 roots of the first term.
Date Posted:
1 year ago
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