Wee Wen Shih's answer to LockB's Junior College 1 H2 Maths Singapore question.
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Correct expression should have been
h(x) = [u(x) - u(x-5)] |x - 2|
The signal |x - 2| is switched on between x=0 and x=5, so that explains the shape of the graph I sketched.
Highest value of h(x) is 3 and lowest value of h(x) is 0, hence 0 <= h(x) <= 3.
Thank you.
h(x) = [u(x) - u(x-5)] |x - 2|
The signal |x - 2| is switched on between x=0 and x=5, so that explains the shape of the graph I sketched.
Highest value of h(x) is 3 and lowest value of h(x) is 0, hence 0 <= h(x) <= 3.
Thank you.
Date Posted:
2 years ago
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