Maximus Lim's answer to Rui Er is here's Primary 6 Maths Fractions Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Let the initial number of girls and boys be x and y respectively.
x = y + 40 — (1)
3/5x = 2/3y + 18
9/5x = 2y + 54
9x = 10y + 270 — (2)
Since x = y + 40,
9(y + 40) = 10y + 270
9y + 360 = 10y + 270
10y - 9y = 360 - 270
y = 90
x = y + 40
x = 90 + 40
x = 130
Total number of girls and boys = x + y = 130 + 90 = 220
x = y + 40 — (1)
3/5x = 2/3y + 18
9/5x = 2y + 54
9x = 10y + 270 — (2)
Since x = y + 40,
9(y + 40) = 10y + 270
9y + 360 = 10y + 270
10y - 9y = 360 - 270
y = 90
x = y + 40
x = 90 + 40
x = 130
Total number of girls and boys = x + y = 130 + 90 = 220
Date Posted:
2 years ago
Apologies, my previous answer had the careless mistake of misreading the question. I have since deleted and republished it!
Thanks
Method use is for sec not P6. Teacher will not except this solving.
360 Tutoring Program