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Question
primary 6 | Maths
| Fractions
3 Answers Below
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Don't know how to solve !
Date Posted: 2 years ago
Views: 514
https://ask.manytutors.com/questions/115684
https://ask.manytutors.com/questions/98645
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Let the initial number of girls and boys be x and y respectively.
x = y + 40 — (1)
3/5x = 2/3y + 18
9/5x = 2y + 54
9x = 10y + 270 — (2)
Since x = y + 40,
9(y + 40) = 10y + 270
9y + 360 = 10y + 270
10y - 9y = 360 - 270
y = 90
x = y + 40
x = 90 + 40
x = 130
Total number of girls and boys = x + y = 130 + 90 = 220
x = y + 40 — (1)
3/5x = 2/3y + 18
9/5x = 2y + 54
9x = 10y + 270 — (2)
Since x = y + 40,
9(y + 40) = 10y + 270
9y + 360 = 10y + 270
10y - 9y = 360 - 270
y = 90
x = y + 40
x = 90 + 40
x = 130
Total number of girls and boys = x + y = 130 + 90 = 220
Apologies, my previous answer had the careless mistake of misreading the question. I have since deleted and republished it!
Thanks
Method use is for sec not P6. Teacher will not except this solving.
done
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is this more applicable?
Date Posted:
2 years ago
Thanks and appreciate. Your explanation is simple to understand.
:)
https://ask.manytutors.com/questions/115684
https://ask.manytutors.com/questions/98645
https://ask.manytutors.com/questions/98645
Thanks and appreciate. Simple to understand with models.
welm
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