help's answer to Jonathan's Secondary 4 Chemistry Singapore question.

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Help's answer
44 answers (A Helpful Person)
1st
at the start the pH is 2 so solution Q is a strong acid (D is out ethanoic acid is weak)
as solution J is added it only reaches pH 7 and just stops there so J is a weak alkali/ base
aq ammonia and potassium oxide r strong so B is the ans

im sorry for my bad explanation