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at the start the pH is 2 so solution Q is a strong acid (D is out ethanoic acid is weak)
as solution J is added it only reaches pH 7 and just stops there so J is a weak alkali/ base
aq ammonia and potassium oxide r strong so B is the ans
im sorry for my bad explanation
as solution J is added it only reaches pH 7 and just stops there so J is a weak alkali/ base
aq ammonia and potassium oxide r strong so B is the ans
im sorry for my bad explanation